Precalc
Section 7.2

Sum & Difference Identities

Sum and difference identities let you compute exact values for angles like $75°$ or $\frac{\pi}{12}$ that aren't on the unit circle. They're also the foundation for the double-angle formulas in Section 7.3. Expect 1–2 'find the exact value' problems on Exam 3.

⚡ Quick Summary

What if you need the exact sine of 75°? It's not on the unit circle — but you can split it into two angles that are: 75°=45°+30°75° = 45° + 30°. The sum and difference formulas let you calculate exact trig values for these "in-between" angles by combining values you already know. The key thing to accept upfront: sin⁡(A+B)\sin(A + B) is not sin⁡(A)+sin⁡(B)\sin(A) + \sin(B). There's a specific formula you have to use.

Sine of a Sum
sin⁡(A+B)=sin⁡Acos⁡B+cos⁡Asin⁡B\sin(A + B) = \sin A \cos B + \cos A \sin B
Sine of a Difference
sin⁡(A−B)=sin⁡Acos⁡B−cos⁡Asin⁡B\sin(A - B) = \sin A \cos B - \cos A \sin B

📋 Before You Start

Tap any item if you need a refresher:

Plain-English version

What if you need the exact sine of 75°? It's not on the unit circle — but you can split it into two angles that are: 75°=45°+30°75° = 45° + 30°. The sum and difference formulas let you calculate exact trig values for these "in-between" angles by combining values you already know. The key thing to accept upfront: sin⁡(A+B)\sin(A + B) is not sin⁡(A)+sin⁡(B)\sin(A) + \sin(B). There's a specific formula you have to use.

The formulas follow a pattern. For sine, the functions alternate: sin⁡(A+B)=sin⁡Acos⁡B+cos⁡Asin⁡B\sin(A + B) = \sin A \cos B + \cos A \sin B — think "sine-cosine-cosine-sine." For cosine, each function sticks with its own kind: cos⁡(A+B)=cos⁡Acos⁡B−sin⁡Asin⁡B\cos(A + B) = \cos A \cos B - \sin A \sin B. The sneaky part: cosine uses the opposite sign — cos⁡(A+B)\cos(A + B) has a minus, and cos⁡(A−B)\cos(A - B) has a plus. It's the reverse of what you'd guess.

The most useful angle splits to memorize: 75°=45°+30°75° = 45° + 30°, 15°=45°−30°15° = 45° - 30°, π12=π3−π4\frac{\pi}{12} = \frac{\pi}{3} - \frac{\pi}{4}, and 7π12=π3+π4\frac{7\pi}{12} = \frac{\pi}{3} + \frac{\pi}{4}. If the problem gives you sin⁡A\sin A and cos⁡B\cos B with quadrant info instead of angles, just find the missing trig values using sin⁡2+cos⁡2=1\sin^2 + \cos^2 = 1 before plugging into the formula.

This is one of the formula-heaviest sections — don't try to memorize everything at once. Focus on the sine and cosine sum formulas first, and remember: "sine-cosine-cosine-sine" for the sine formula, and "cosine is contrary" for the sign in the cosine formula.

Key Formulas

Sine of a Sum
sin⁡(A+B)=sin⁡Acos⁡B+cos⁡Asin⁡B\sin(A + B) = \sin A \cos B + \cos A \sin B
Sine of a Difference
sin⁡(A−B)=sin⁡Acos⁡B−cos⁡Asin⁡B\sin(A - B) = \sin A \cos B - \cos A \sin B
Cosine of a Sum
cos⁡(A+B)=cos⁡Acos⁡B−sin⁡Asin⁡B\cos(A + B) = \cos A \cos B - \sin A \sin B

Watch the sign — it's minus for the sum, which is the opposite of what you might guess.

Cosine of a Difference
cos⁡(A−B)=cos⁡Acos⁡B+sin⁡Asin⁡B\cos(A - B) = \cos A \cos B + \sin A \sin B
Tangent of a Sum/Difference
tan⁡(A±B)=tan⁡A±tan⁡B1∓tan⁡Atan⁡B\tan(A \pm B) = \frac{\tan A \pm \tan B}{1 \mp \tan A \tan B}

The sign in the denominator is opposite to the sign in the numerator.

Key Takeaways

  • ✓sin⁡(A+B)≠sin⁡A+sin⁡B\sin(A + B) \neq \sin A + \sin B — you must use the formula: sin⁡Acos⁡B+cos⁡Asin⁡B\sin A \cos B + \cos A \sin B
  • ✓Cosine formulas have the opposite sign: cos⁡(A−B)\cos(A - B) has a plus, cos⁡(A+B)\cos(A + B) has a minus
  • ✓Key decompositions to memorize: 75°=45°+30°75° = 45° + 30°, 15°=45°−30°15° = 45° - 30°, π12=π3−π4\frac{\pi}{12} = \frac{\pi}{3} - \frac{\pi}{4}
  • ✓If given sin⁡A\sin A and cos⁡B\cos B with quadrant info, find the missing values via sin⁡2+cos⁡2=1\sin^2 + \cos^2 = 1 first

⚠️ Common Mistakes

  • ✗Thinking sin⁡(A+B)=sin⁡A+sin⁡B\sin(A + B) = \sin A + \sin B — this is wrong; you must use the full formula sin⁡Acos⁡B+cos⁡Asin⁡B\sin A\cos B + \cos A\sin B
  • ✗Getting the sign wrong in the cosine formula — cos⁡(A+B)\cos(A + B) uses minus and cos⁡(A−B)\cos(A - B) uses plus, which is the opposite of what you'd guess
  • ✗Not knowing how to decompose non-standard angles — memorize these: 75°=45°+30°75° = 45° + 30°, 15°=45°−30°15° = 45° - 30°, π12=π3−π4\frac{\pi}{12} = \frac{\pi}{3} - \frac{\pi}{4}
  • ✗Forgetting to find missing trig values before plugging in — if given sin⁡A\sin A and a quadrant, find cos⁡A\cos A first via sin⁡2+cos⁡2=1\sin^2 + \cos^2 = 1